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Find the magnetic induction due to a straight conductor of length 16cm carrying current of 5A at a distance of 6cm from the midpoint of conductor |
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Answer» Solution :`B=(mu_(0))/(4PI)I/r(sintheta+sintheta)` but `sintheta=8/10=4/5` `B=10^(-7)XX5/(6xx10^(-2))xx2xx4/5` `=40/3muT`
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