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Find the magnitude of the centripetal acceleration of a car following a curve of radius 500 m at a speed of 25.0 m/s (about 90 km/h). Compare the acceleration with that due to gravity for this fairly gentle curve taken at high speed. |
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Answer» Solution :As the values of v and R are given, the expression `a=v^(2)//R` is the most suitable to use. Calculation: Substituting the values of v and r into `a=v^(2)//R` gives `a=(v^(2))/R=((25.0m//s)^(2))/(500m)=1.25m//s^(2)` On comparing this with the acceleration DUE to gravity `(g=9.80m//^(2))`, we consider the ratio of a/g, `a/g=(1.25m//s^(2))/(9.80m//s^(2))=0.128` Thus a=0.128g, which is apparent, PARTICULARLY if you were not wearing a SEAT belt. |
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