Find the magnitude of the force acting along the direc tion -6hati +2hatj +3hatk which displaces a particle from position (2, -1, 0) to a new position (1, 2, -1) and in doing so does a work of 5 units :

Find the magnitude of the force acting along the direc tion -6hati +2h

1.	Find the magnitude of the force acting along the direc tion -6hati +2hatj +3hatk which displaces a particle from position (2, -1, 0) to a new position (1, 2, -1) and in doing so does a work of 5 units :
Answer» 7/3 units `(3)/(7)` units `(5)/(6)` units `(6)/(5)` units Solution :`vecS=vecS_2+vecS_1=(1-2)hati+(2+1)HATJ+(-1-0)hatk` =`hati+3hatj-hatk` Let \|F\| be the magnitude of the force then `vecF=\|F\|xx"UNIT vector along the direction of force"` `vecF=\|F\|xx([-6hati+2hatj-3hatk])/(sqrt(36+4+9))=(F)/(7)[-6hati+2hatj-3hatk]` Now `W=vecF.vecS` `:. 5=F/7[-6hati+2hatj-3hatk].[-hati+3hatj-hatk]` =`F/7(6+6+3)` or 35=15 F or `\|F\|=(35)/(15)=(7)/(13)`units.

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Find the magnitude of the force acting along the direc tion -6hati +2hatj +3hatk which displaces a particle from position (2, -1, 0) to a new position (1, 2, -1) and in doing so does a work of 5 units :

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