InterviewSolution
Saved Bookmarks
| 1. |
Find the magnitude of \(\vec{a}\) and \(\vec{b}\) which are having the same magnitude and such that the angle between them is 60° and their scalar product is \(\frac{1}{4}\).(a) \(|\vec{a}|=|\vec{b}|=\frac{1}{2√2}\)(b) \(|\vec{a}|=|\vec{b}|=\frac{1}{√2}\)(c) \(|\vec{a}|=|\vec{b}|=\frac{1}{2√3}\)(d) \(|\vec{a}|=|\vec{b}|=\frac{2}{√3}\)I have been asked this question by my college director while I was bunking the class.The question is from Product of Two Vectors-2 in portion Vector Algebra of Mathematics – Class 12 |
|
Answer» RIGHT answer is (a) \(|\vec{a}|=|\vec{b}|=\FRAC{1}{2√2}\) The best I can EXPLAIN: Given that: a) \(|\vec{a}|=|\vec{b}|\) b) θ=60° c) \(\vec{a}.\vec{b}=\frac{1}{4}\) ∴\(|\vec{a}||\vec{b}| cosθ=\frac{1}{4}\) =\(|\vec{a}|^2 cos60°=\frac{1}{4}\) ⇒\(|\vec{a}|^2=\frac{1}{4}.\frac{1}{2}\) ∴\(|\vec{a}|=|\vec{b}|=\frac{1}{2√2}\). |
|