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Find the matrix A such that `[{:(2,-1), (1,0),(-3,4):}]A=[{:(-1,-8,-10),(1,-2,-5),(9,22,15):}]` |
Answer» we have, `[{:(2,-1),(1,0),(-3,4):}]_(3xx2)A=[{:(-1,-8,-10),(1,-2,-5),(9,22,15):}]_(3xx3)` From the given equation , it is clear that order of A should be `2xx3` Let `A=[{:(a,b,c),(d,e,f):}]` `[{:(2,-1),(1,0),(-3,4):}][{:(a,b,c),(d,e,f):}]=[{:(-1,-8,-10),(1,-2,-5),(9,22,15):}]` `rArr[{:(2a-d,2b-e,2c-f),(a+0d,b+0.e,c+0.f),(-3a+4d,3b+4e,-3c+4l):}]=[{:(-1,-8,-10),(1,-2,-5),( 9,22,15):}]` `rArr [{:(2a-d,2b-e,2c-f),(a,b,c),(-3a+4d,-3b+4e,-3c+4f):}]=[{:(-1,-8,-10),(1,-2,-5),(9,22,15):}]` By equality of matrices, we get `a=1,b=-2,c=-5` and `2a-d=-1rArrd=2a+1=3` `rArr 2b-e=-8rArre=2(-2)+8=4` 2c-f=-10`rArr`f=2c+10=0 `therefore A=[{:(1,-2,-5),(3,4,0):}]` |
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