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Find the maximum magnitude of the linear momentum of a photoelectron emitted when light of wavelength 400 nm falls on a metal having work function 2.5e V. |
Answer» Correct Answer - `(P^(2))/(2m)((1.24xx10^(4))/(4000)-2.5)eV=0.6eV` `P=sqrt(2xx9.1xx10^(-31)xx0.6xx1.6xx10^(-19))` `=4.2xx10^(-25)kg.m//s` |
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