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Find the maximum number of students among whom 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and the same number of pencils. |
Answer» Given: Total number of pens = 1001 Total number pencils = 910 Maximum number of students who get the same number of pens and the same number of pencils = HCF (1001 and 910) Using prime factorization: 910 = 2 x 5 x 7 x 13 1001 = 7x 11 x 13 Now, HCF(1001 and 910) = 91 Answer: 91 students get same number of pens and pencils. |
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