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Find the maximum value of 1+sin(pi/4+theta) + 2cos(pi/4-theta). |
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Answer» Solution :We have , `1+sin(pi/4+theta)+2cos(pi/4-theta)` `=1+1/sqrt(2)(costheta+sintheta) + sqrt(2)(costheta+sintheta) = 1+1/sqrt(2(+sqrt(2))(costheta+sintheta)` `=1+(1/sqrt(2)+sqrt(2)).sqrtcos(theta-pi/4)` `therefore` maximum VALUE`=1+(1/sqrt(2)+sqrt(2)).sqrt(2)=4` |
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