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Find the maximum value of `(7-x)^4(2+x)^5w h e nx`lies between `-2a n d7.` |
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Answer» Since `- 2 lt x lt 7` `:. X + 2 gt 0` and `7 - x gt 0` We have to find maximum value of `(7 - x)^(4) (2 + x)^(5)` or `p^(4) q^(5` where P + q = 9 `(4((p)/(4)) + ((q)/(5)))/(5 + 5) ge [((p)/(5))^(4) ((q)/(5))^(5)]^((1)/(9)` `implies [((p)/(4))^(4) ((q)/(5))^(5)]^((1)/(9)) le (p + q)/(9)` `implies ((p)/(4))^(4) ((q)/(5))^(5 le 1` `implies p^(4) q^(5) le 4^(4) 5^(5)` Therefore, maximum value of `(7 - x)^(4) (2 + x)^(5)` is `4^(4) 5^(5)` |
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