1.

Find the maximum value of current when a coil of inductance 2H is connected to 150V, 50 cycles/sec supply.

Answer»

SOLUTION :Here `L=2H, E_("rms")=150V, V=50Hz`
`X_(L)=Lomega=Lxx2piv=2xx2xx3.14xx50="628 ohm"`
RMS value of current through the INDUCTOR,
`I_("rms")=(E_("rms"))/(X_(L))=(150)/(628)=0.24A`
Maximum value *or PEAK value) of current is given by
`I_("rms")=(I_(0))/(sqrt2)` or `I_(0)=sqrt2""I_("rms")=1.414xx0.24=0.339A`


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