1.

Find the mean deviation about the mean of the distributon .

Answer»


Solution :
Now`M_(e)=(20+1/(2)) th item =(21/2)=10.5 th item`
`thereforeM_(e)=12 `
`thereforeMD=(Sigmaf_(i)d_(i))/(SIGMA f_(i))=(25)/(20)=1.25`


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