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Find the mean deviation about the median for the data in Question |
Answer» Solution :![]() Here `N=26` `:.` Median `M=(N/2 "th TERM" + (N/2+1) "th term")/2` `=(26/2 "th term"+(26/2+1)"th term")/2` `=(13 "th term"+14 "th term")/2` `=(7+7)/2=7` Now mean DEVIATION `=(sumf_(i)|x_(i)-M|)/(sumf_(i))=84/26=3.23` |
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