1.

Find the mean deviation about the median for the data given below. 45, 36, 50, 60, 53, 46, 51, 48, 72, 42.

Answer» Arranging the given data in an ascending order, we get :
36, 42, 45, 46, 48, 50, 51, 53, 60, 72.
Here n=10, which is even.
`therefore" median"=(1)/(2).{(n)/(2)"th observation"+((n)/(2)+1)"th observation"}`
`=(1)/(2)("5th observation + 6th observation")`
`=(1)/(2)(48+50)=(98)/(2)=49.`
Thus, M=49.
The values of `(x_(i)-M)` are
`-13,-7,-4,-3,-1,1,2,4,11,23.`
`therefore" "overset(10)underset(i=1)Sigma|x_(i)-M|=(13+7+4+3+1+1+2+4+11+23)=69`
`rArr" "MD(M)=(overset(10)underset(i=1)Sigma|x_(i)-M|)/(10)=(69)/(10)=6.9.`


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