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Find the mean - proportional of `(a + b)^(2)" and " (a - b)^(2)`. |
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Answer» Let the mean - proportional of `(a+b)^(2) " and " (a - b)^(2) ` be x. ` :. ((a +b)^(2))/x = x/((a-b)^(2))` or, ` x^(2) = ( a + b)^(2) xx (a - b)^(2)` or, ` x^(2) = {(a + b)(a - b)^(2) " or, " x^(2) = (a^(2) - b^(2))^(2)`. or, ` x = pm(a^(2) - b^(2))` Hence the required mean - proportional `= pm (a^(2) - b^(2))`. |
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