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Find the mean radiation power of an electorn performing harmonic oscillations with amplitude a = 0.10 nm and frequency omega = 6.5.10^(14)s^(-1) |
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Answer» Solution :`P = (1)/(4piepsilon_(0)) (2(dotoversetrarr(p))^(2))/(3c^(3))` `|dotoversetrarr(p)|^(2) = (e omega^(2)a)^(2) cos^(2) omegat` Thus `lt PGT= (1)/(4PI epsilon_(0)) (2)/(3c^(2)) (e omega^(2)a)^(2) xx (1)/(2) = (e^(2)omega^(4)a^(2))/(12pi epsilon_(0)C^(3)) = 5.1 xx 10^(-15)W`. |
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