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Find the mean variance and standard deviation using short-cut method |
Answer» SOLUTION :![]() Let assumed mean `A=92.5` and `h=5` Mean `barx=A+(sumf_(i)d_(i))/(sumf_(i))xxh=62.5+(6xx5)/60=93` VARIANCE `sigma^(2)=h^(2)[((sumf_(i)d_(i)^(2)))/N-((sumf_(i)d_(i))/N)^(2)]` `=5^(2)[254/60-(6/60)^(2)]` `=25/(60^(2))[15240-36]` `=1/144xx15204=105.58` STANDARD deviation `=SQRT(105.58)` `=10.28` |
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