1.

Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle.

Answer»

Given, 

Let the smallest angle = x 

Than the other angle = (2x – 24)° 

So, 

x+x+2x – 24 + 2x – 24 = 360 

6x = 360 + 48 = 408

x = \(\frac{408^∘}{6}\) = 68

Other angles = 2x – 24 = 2×68 – 24 = 136-24 = 112 

Angles are = 68, 68, 112, 112



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