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Find the measure of all the angles of a parallelogram, if one angle is 24° less than the twice of the smallest angle. |
Answer» Then its consecutive angle = 180 – x° By problem (180 – x)° = (2x- 24)° (∵ opp. angles are equal) 180 + 24 = 2x + x 3x = 204 x = 204/3 = 68° ∴ The angles are 68°; (2 x 68 – 24)°; 68°; (2 x 68 – 24)° = 68°, 112°, 68°, 112° |
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