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Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle. |
Answer» Given: One angle of a parallelogram is 24° less than twice the smallest angle. Let x be the smallest angle, then x + 2x – 24° = 180° 3x – 24° = 180° 3x = 108° + 24° 3x = 204° x = 204°/3 = 68° So, x = 68° Another angle = 2x – 24° = 2(68°) – 24° = 112° Hence, four angles are 68°, 112°, 68°, 112°. |
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