Find the measure of each interior angle of a regular polygon having(i)

1.	Find the measure of each interior angle of a regular polygon having(i) 10 sides(ii) 15 sides
Answer» In a regular polygon having 10 sides, all sides are same size and measure of all interior Angles are Same. The sum of interior angles of polygon is (n-2) × 180^o where n is the number of sides of polygon. (10-2) × 180^o =1440^ohere n=10 Each interior angle= 1440/10 = 144^o (ii) In a regular polygon, all sides are same size and measure of all interior angles are Same. The sum of interior angles of polygon of 15 sides is (n-2) × 180^o where n is the number of sides of polygon. (15-2) × 180^o =1440^ohere n=15 Each interior angle= 2340/15 = 156^o

Find the measure of each interior angle of a regular polygon having(i) 10 sides(ii) 15 sides

Answer»

In a regular polygon having 10 sides, all sides are same size and measure of all interior

Angles are

Same.

The sum of interior angles of polygon is

(n-2) × 180^o where n is the number of sides of polygon.

(10-2) × 180^o =1440^ohere n=10

Each interior angle= 1440/10 = 144^o

(ii) In a regular polygon, all sides are same size and measure of all interior angles are

Same.

The sum of interior angles of polygon of 15 sides is

(n-2) × 180^o where n is the number of sides of polygon.

(15-2) × 180^o =1440^ohere n=15

Each interior angle= 2340/15 = 156^o