1.

Find the measure of 'x'(a)A122°ХB.128°°​

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Answer:

See Explanation

Step-by-step explanation:

SUM of all INTERIOR angles of QUADRILATERAL =3600

∴50+130+120+x=300

x=600

(b) 

90+a=180

a=90

Sum of all angles of QUAD =360

x+70+60+90=360

x=1400

(c) 

70+a=180 (Linear pair)

a=110

60+b=180 (Linear pair)

b=120

Sum of measures of all angles of pentagon =5400

∴120+110+x+x+30=540

2x=280

x=1400

(d) 

Sum of all angles of pentagon 540

Given all angles are equal

∴5x=540

x=1080



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