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Find the measure of 'x'(a)A122°ХB.128°° |
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Answer» Answer: See Explanation Step-by-step explanation: SUM of all INTERIOR angles of QUADRILATERAL =3600 ∴50+130+120+x=300 x=600 (b) 90+a=180 a=90 Sum of all angles of QUAD =360 x+70+60+90=360 x=1400 (c) 70+a=180 (Linear pair) a=110 60+b=180 (Linear pair) b=120 Sum of measures of all angles of pentagon =5400 ∴120+110+x+x+30=540 2x=280 x=1400 (d) Sum of all angles of pentagon 540 Given all angles are equal ∴5x=540 x=1080 |
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