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Find the middle term in the expansion of `(x^2+1/(x^2)+2^n)dot` |
Answer» Correct Answer - `((2n)!)/((n!)^(2))` `(x^(2)+1/(x^(2))+2)^(n) = (x+1/x)^(2n)` Hence, the middle term is `T_((2n)/(2)+1) = T_(n+1) = .^(2n)C_(n)(x)^(n)(1/x)^(n) = .^(2n)C_(n)= ((2n)!)/((n!)^(2))` |
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