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find the minimum diameter of steel wire which is used to raise a load of 4000 N if the stress in the rod is not exceed 95mn/m2 |
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Answer» Answer: d Explanation: As STRESS = load / area Area = load/stress Also, area is π/4 D2 so π/4 D2 = 4000 / 95 And D = 7.32. |
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