1.

find the minimum diameter of steel wire which is used to raise a load of 4000 N if the stress in the rod is not exceed 95mn/m2​

Answer»

ANSWER:

Answer: d

Explanation: As STRESS = load / area

Area = load/stress

Also, area is π/4 D2 so π/4 D2 = 4000 / 95

And D = 7.32.



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