Find the minimum energy that a `gamma`-ray must have to give rise to an electron -positron pair. `{:("Mass of electron",= 0.00055 am u,),("Mass of positron",= 0.00055 am u,):}`

Find the minimum energy that a `gamma`-ray must have to give rise to a

1.	Find the minimum energy that a `gamma`-ray must have to give rise to an electron -positron pair. `{:("Mass of electron",= 0.00055 am u,),("Mass of positron",= 0.00055 am u,):}`
Answer» Correct Answer - 1.024 MeV

Calculate the amount of energy set free by the annigilation of an electron and a positron. Given that mass of electron `= 0.00055` amu and positron = 0.00055 amu.
The nucleus `._(92)^(235)U` decays according to `._(92)^(238)U rarr ._(92)^(234)Th + ._(2)^(4)He`. Calculate the kinetic energy of the emitted `alpha`-particle `._(92)^(238)U = 3.85395 xx 10^(-25) kg " " ._(90)^(234)Th = 3.78737 xx 10^(-25) kg " " ._(2)^(4)He = 6.64807 xx 10^(-27)`
Calculate the energy released in kilowatt-hours when 100g of `._(3)^(7)Li` are converted into `._(2)^(4)He` by proton bombardment. Mass of `._(3)^(7)Li = 7.0183 am u`, mass of proton = 1.0081 amu. Write down the nuclear reaction.
Calculate the binding energy of the lithium atom `(._(3)^(7)Li)` from the following data: `{:("mass of proton",= 1.00759,am u,),("mass of neutron",= 1.00898,am u,),("mass of electron",= 0.00055,am u,),("mass of lithium atom",= 7.01818,am u,):}`
Find the minimum energy that a `gamma`-ray must have to give rise to an electron -positron pair. `{:("Mass of electron",= 0.00055 am u,),("Mass of positron",= 0.00055 am u,):}`