1.

Find the minimum speed required by a person standing 5 m behind a bus, to catch the bus in one minute which is moving at a speed of 600 m min^(-1).

Answer»

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Solution :
`5+S_(b) = V_(P)t`
`S_(b) = 600 xx 1`
`5 + (600 xx 1) = V_(P) xx 1`
`V_(P) = 605` m `MIN^(-1)`


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