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1. |
Find the missing frequency (p) for the following distribution whose mean is 7.68.x35791113f6815p84 |
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Answer»
We know that, Mean = \(\frac{Σ fx}{ N }\) = \(\frac{(303 + 9p)}{(41 + p) }\) Given, Mean = 7.68 ⇒ 7.68 = \(\frac{(303 + 9p)}{(41 + p)}\) 7.68(41 + p) = 303 + 9p 7.68p + 314.88 = 303 + 9p 1.32p = 11.88 ∴ p = \(\frac{11.88}{1.32}\) = 9 |
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