1.

Find the missing value of p for the following distribution whose mean is 12.58x:581012p2025y:25822742

Answer»
Xyyx
5210
8540
10880
1222264
p77p
20480
25250
N = 50\(\sum\)yx = 524 + 7p

Given,

Mean = 12.58

\(\frac{\sum yx}{N}=12.58\)

\(\frac{524+7p}{50}=12.58\)

524 + 7p = 12.58 (50)

7p = 629 – 524

p = \(\frac{105}{7}=15\)



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