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Find the molality of 1.0 L solution of 90% `H_2SO_4` by weight/volume. The density of the solution is 1.47 `gc c^(-1)` |
Answer» (a). `90% H_2SO_4 (weight)/(volume)implies(90g)/(100mL)` `implies(Mass)/(L)=900g` `("Mass of solution")/(L)=1000xx1.47=1470g` `impliesMass of H_2O=1470-900=570g` `m=((900)/(98))/(570)xx1000=16.11` |
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