InterviewSolution
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Find the most general value of θ satisfying the equation tanθ = –1 and cosθ = 1/√2 |
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Answer» We have tan θ = -1 and cos θ =1/√2 . So, θ lies in IV quadrant. θ = 7π/4 So, general solution is θ = 7π/4 + 2 n π, n ∈ Z |
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