1.

Find the most general value of θ satisfying the equation tanθ = –1 and cosθ = 1/√2

Answer»

We have tan θ = -1 and cos θ =1/√2 .

So, θ lies in IV quadrant.

θ = 7π/4

So, general solution is θ = 7π/4 + 2 n π, n ∈ Z



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