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Find the most general value of θ satisfying the equation tan θ = –1 and cos θ = 1/√2. |
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Answer» According to the question, We have, tan θ = -1 And cos θ =1/√2 . ⇒ θ = – π/4 So, we know that, θ lies in IV quadrant. θ = 2π – π/4 = 7π/4 So, general solution is θ = 7π/4 + 2 n π, n∈ Z |
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