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Find the mutual inductance between the circular coil and the loop shownin figure. |
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Answer» SOLUTION :emf induced =(mu_(0)(a_1)^2 (a_2)^2 Erv)/(2L(a^(2)+x^(2))^(3//2)((Rx)+R^(2))` [From question 20] `(d phi)/(dt)=(ERV)/(L((Rx)/(L)+r)^2)` M=(E )/((DI)/(dt))=(N(mu_0)(pi)a^(2)a^(2))/(2 (a^(2)+x^(2))^(3//2))`. |
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