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Find the n factor of KMnO_(4) in difference medium . |
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Answer» Solution :(i) In acidic medium `KMnO_(4) rarr Mn^(-2)` CHANGE in oxidation number of `Mn+ 7 -2=5` `:.` the n factor of `KMnO_(4) = 5` (ii) stronggly basic medium `KMnO_(4) rarr K_(2) MnO_(4)` n factor of `KMnO_(4) = +7- 6 = 1` (iii) NEUTRAL mediumor weakly basic medium `KMnO_(4) rarr MnO_(2)` n factor of `KMnO_(4) = +7 - 4 =3` |
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