Given : tan (N*15°)  + cot ( N*15°) is an integer

To Find : number of 2-digit positive integers N

Solution:

tan (N*15°)  + cot ( N*15°)

= Sin (N*15°)/Cos (N *15°) +  Cos (N *15°) /Sin (N*15°)

= ( Sin² (N*15°) + Cos² (N *15°) )/ Sin (N*15°)  Cos (N *15°)

=  1/ Sin (N*15°)  Cos (N *15°)

= 2/ 2 Sin (N*15°)  Cos (N *15°)

= 2/ Sin (N * 30°)

Sin (N * 30°) =±1  or    Sin (N * 30°) = ±1/2     will give an integer

Sin (N * 30°) =  Sin (180°n  + 90° )

=> N * 30° =180°n  + 90°

=> N = 6n  + 3

k  from 2  to  16 will given N = 15  to 99  HENCE 15 such numbers

N = 15 , 21 ,27 , 33 , 39 , 45 , 51 , 57 ,63 , 69 ,  75 , 81 ,87 , 93 ,99

Sin (N * 30°) =±1/2  

N * 30°   = n*180° ± 30°  

=> N  =  6n ± 1

N  = 6n + 1        n = 2 to  16   N from 13 to 97  Hence 15 such numbers

N =  13 , 19,  25 , 31 ,  37 ,43 ,  49 , 55 ,61 ,  67 ,  73 , 79 , 85 , 91 , 97

N = 6n - 1           n = 2 to  16   N from 11 to 95    Hence 15 such numbers

N = 11, 17 , 23, 29 ,35 , 41 , 47 , 53 , 59,  65 , 71 , 77 , 83 , 89 , 95

Hence 15 + 15 + 15 = 45  Such 2 Digits numbers are possible

where tan (N*15°)  + cot ( N*15°) is integer  

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