1.

Find the number of digits in 42013, if log102 = 0.3010.

Answer»

Given : 

log102 = 0.3010 

42013 = (22)2013 = 24026

∴ log1024026 = 4026 log10

[∵ log xm= m log x] 

= 4026 × 0.3010 = 1211.826. 

So 1211 + 1 = 1212 

∴ 42013 has 1212 digits in its expansion. 

(∵ characteristic 1211)



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