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Find the number of digits in 42013, if log102 = 0.3010. |
Answer» Given : log102 = 0.3010 42013 = (22)2013 = 24026 ∴ log1024026 = 4026 log102 [∵ log xm= m log x] = 4026 × 0.3010 = 1211.826. So 1211 + 1 = 1212 ∴ 42013 has 1212 digits in its expansion. (∵ characteristic 1211) |
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