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Find the number of digits in 810, given that log 2 = 0.301 |
Answer» 10 Digits WOULD be there in 8¹⁰Step-by-step explanation: We NEED to find the number of digits in 8¹⁰ Let say N = 8¹⁰ Taking LOG both sides Log N = Log (8¹⁰) => Log N = 10 Log 8 => Log N = 10 Log 2³ => Log N = 10 * 3 Log 2 => Log N = 30 Log 2 Log 2 = 0.301 => Log N = 30 * 0.301 => Log N = 9.03 Log N ≥ 9 => 10 Digits would be there in 8¹⁰ N = 10^(9.03) for 10ˣ - numberof digits = x + 1 9 ≤ x < 10 => number of digits = 10 Learn more: If log2 = 0.30103 and log 3 = 0.4771, find the number of digits in ... the number of digits in a number is x, find the POSSIBLE number of ... |
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