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Find the number of half lives elapsed , before which , 93.75% of a radioactive sample has decayed . |
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Answer» Solution :Fraction of ATOMS left undecayed is 100 - 93.75% i.e `N/N_(0)=(6.25)/100 = 1/(16)` or , `N/N_(0) = (1/2)^(4) ` or `N = N_(0) (1/2)^(4)` Comparing with `N = N_(0) (1/2)^(n) , ` yields n = 4 . |
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