1.

Find the number of half lives elapsed , before which , 93.75% of a radioactive sample has decayed .

Answer»

Solution :Fraction of ATOMS left undecayed is
100 - 93.75%
i.e `N/N_(0)=(6.25)/100 = 1/(16)`
or , `N/N_(0) = (1/2)^(4) ` or `N = N_(0) (1/2)^(4)`
Comparing with `N = N_(0) (1/2)^(n) , ` yields n = 4 .


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