InterviewSolution
Saved Bookmarks
| 1. |
Find the number of solutions of tanx + secx = 2cosx in [0,2pi] |
|
Answer» Solution :Here, `tanx + secx = 2cosx rArr SINX +1=2cos^(2)x` `rArr 2SIN^(2)x+sinx-1=0 rArr sinx=1/2, -1` But `sinx=-1 rArr x=(3pi)/(2)` for which `tanx+secx =2 cosx` is not DEFINED. THUS, `sinx=1/2 rArr x=pi/6, (5pi)/(6)` `rArr` number of solutions of `tanx+secx = 2cos x` is 2.Ans. |
|