Find the number of terms of AP 7,13,19.............................. 2

1.	Find the number of terms of AP 7,13,19.............................. 205.
Answer» $\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$ $= >n = 34$ $\Large{\underline{\underline{\bf{QuEsTiOn:-}}}}$ How many term are these in the AP 7,13,19,...........205? $\huge\underline\mathbb{\red S\pink {0} \purple {L} \blue {UT} \orange {1}\green {ON :}}$ Given sequence is 7,13,19,...,205 Given sequence is 7,13,19,...,205The first term a=7 and The COMMON DIFFERENCE d=13−7=6 The last term is 205 Let the last term be the nth term. We KNOW that the nth term of the arithmetic progression is given by - $= > a+(n−1)d$ $= > a+(n−1)d=205$ $= > 7+(n−1)×(6)=205$ $= > 7− \: 6+6n=205$ $= > 1+6n=205$ $= > 6n=205−1$ $= > 6n = 204$ $= >n = \frac{204}{6}$ $= > n = 34$ $\sf\underline{\underline{\green{THEREFORE, \: }}}$ The number of terms in the given sequence is 34