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Find the number of terms of the A.P. If 1 is added to each term of this A.P., then find the sum of all terms of the A.P. thus obtained. |
Answer» The given A.P. is -12, -9, -6,…21 Here, a = -12, d = -9 – (-12) = 3 Let the number of terms be n Tn = a + (n – 1) d 21 = -12 + (n – 1) (3) 21 = -15 + 3n 36 = 3n n = 12 If 1 is added to each term than A.P. is -11, -8, -5…20 Here, a = -11, d = 3 S12 = \(\frac{n}{2}\)[2(-11) + (12 -1) x 3] = 6 (-22 + 33) = 66 |
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