1.

Find the number of terms of the A.P. If 1 is added to each term of this A.P., then find the sum of all terms of the A.P. thus obtained.

Answer»

The given A.P. is -12, -9, -6,…21 

Here, a = -12, d = -9 – (-12) = 3 

Let the number of terms be n 

Tn = a + (n – 1) d 

21 = -12 + (n – 1) (3) 

21 = -15 + 3n 

36 = 3n

n = 12 

If 1 is added to each term than A.P. is -11, -8, -5…20 

Here, a = -11, d = 3 

S12\(\frac{n}{2}\)[2(-11) + (12 -1) x 3] = 6 (-22 + 33)

= 66



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