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Find the number of terms of the finite AP3,6, 9, .... 111.​

Answer» N = 111a = 3d = 6-3 =3n = ?FORMULA: TN = a+(n-1)d or, 111 = 3+(n-1)3 or, 111 =3+3n-3 or, 3n =111 or, n =111/3 =37 Ans.


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