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Find the number of the zeros of the polynomial f(X)= (x-1)(x-2)(x-3) |
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Answer» Answer: Step-by-step EXPLANATION: (x-1)(x-2)(x-3)(x-4) = 0 x-1 = 0 ; x = 1 x-2 = 0 ; x = 2 x-3 = 0 ; x = 3 x-4 = 0 ; x = 4 hence the zeroes are :- 1,2,3,4 MARK IT AS THE BRAINLIESTHOPE IT HELPS!!! ^_^ |
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