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find the number of times the perimeter and area of the square field is increased if side of the square field is doubled |
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Answer» let the side of square field be X perimeter = 4x now if you double the side that is 2x New perimeter = 4*2x = 8x HENCE perimeter of square field is doubled now area of square field= x^2 New side is 2x Area of the TRIANGLE so formed = (2x)^2 = 4x^2 Hence the area BECOMES four times the original area Step-by-step explanation: Hope you liked the solution. please Mark me as brainliest |
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