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find the number of times the perimeter and area of the square field is increased if side of the square field is doubled |
Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>let the side of square field be <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> </p><p>perimeter = 4x</p><p>now if you double the side that is 2x</p><p>New perimeter = 4*2x = 8x </p><p><a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> perimeter of square field is doubled</p><p>now area of square field= x^2</p><p>New side is 2x </p><p>Area of the <a href="https://interviewquestions.tuteehub.com/tag/triangle-1427233" style="font-weight:bold;" target="_blank" title="Click to know more about TRIANGLE">TRIANGLE</a> so formed = (2x)^2 = 4x^2</p><p>Hence the area <a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> four times the original area</p><p></p><p><strong>Step-by-step explanation:</strong></p><p>Hope you liked the solution. please Mark me as brainliest</p></body></html> | |