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Find the odd pair of numerical that does NOT hold same relation as the rest.1. 9 - 32. 8 - 43. 10 - 34. 6 - 6 |
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Answer» Correct Answer - Option 3 : 10 - 3 The logic followed is: The first number is exactly divisible by the second number. All the options except for option (3), the first number is exactly divisible by the second number. Option 1: 9 - 3 9 is exactly divisible by 3. Option 2: 8 - 4 8 is exactly divisible by 4. Option 3: 10 - 3 10 is not exactly divisible by 3. Option 4: 6 - 6 6 is exactly divisible by 6. Hence, the correct answer is "10 - 3". |
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