1.

Find the percentage composition of potassium chlorate (KClO_(3))

Answer»


SOLUTION :`"Mol. MASS of "KClO_(3)=39+35.5+48=122.5`
`%" of K"=(39)/(122.5)XX100,%" of Cl"=(35.5)/(122.5)xx100, %" of O"=(48)/(122.5)xx100`


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