1.

find the percentage error in calculating the volume of the cubical box if an error of `1%` is made in measuring the length of the edges of the cube.

Answer» let the edge of cube is `x`
volume `v= x^3`
`(dv)/(dx) = 3x^2`
`del x = dx`
`(dx)/x xx 100 = 1`
`=> dx = x/100`
`dv = del v`
`= (dv)/(dx) xx dx= 3x^2 xx x/100 = (3x^3)/100`
`(dv)/v xx 100 = (3x^3)/(100 xx v) xx 100 `
`= (3x^3)/(100 xx x^3) xx 100`
percentage change in v error=`3%`
Answer


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