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find the percentage error in calculating the volume of the cubical box if an error of `1%` is made in measuring the length of the edges of the cube. |
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Answer» let the edge of cube is `x` volume `v= x^3` `(dv)/(dx) = 3x^2` `del x = dx` `(dx)/x xx 100 = 1` `=> dx = x/100` `dv = del v` `= (dv)/(dx) xx dx= 3x^2 xx x/100 = (3x^3)/100` `(dv)/v xx 100 = (3x^3)/(100 xx v) xx 100 ` `= (3x^3)/(100 xx x^3) xx 100` percentage change in v error=`3%` Answer |
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