Step-by-step explanation:FIND the perimeter of an isosceles RIGHT triangle whose area is 200 cm^2.since , we know that in isosceles triangle two sides are always EQUAL. but here given that the isosceles triangle is right triangle . if the triangle is isosceles right triangle then its base and height will be equal.why hypotenuse will not be equal either to height or base of isosceles right triangle ?its because , according pythagoras theoremif the triangle is right (90°) then the LENGTH of hypotenuse of that triangle will always be greater than the base and the height of that triangle.let b be the hypotenuse and ( a , a ) be the base and height of isosceles right triangle.from ∆ ABCarea of isosceles right triangle=200cm^2( 1 / 2 ) × base × height = 200( 1 × a × a ) / 2 = 200a^2 = 400 => a = √400 => a = 20 cmnow in ∆ ABC ,by Pythagoras theorem , we get(AC)^2 = ( BC )^2 + ( AB )^2b^2 = ( 20 )^2 + ( 20 )^2b^2 = 400 + 400 = 800b = √800 => 28.2 cm ( approx. )since , we know that perimeter of triangle= sum of all the sides of triangle.therefore, perimeter of isosceles right triangle= a + a + b = 20 + 20 + 28.2 = 68.2 cmYour Answer : 68.2 cm THEREFORE, Perimeter of an isosceles right triangle whose area is 200 cm= 68.2 cm