Find the perimeter of rectangle whole length is 40 cm and diagonal is

1.	Find the perimeter of rectangle whole length is 40 cm and diagonal is 41 cm
Answer» Answer: 98cm Step-by-step explanation: By PYTHAGORAS theorem, (DIAGONAL)^2=(Length)^2+(Width)^2 Now as given in the question, Diagonal = 41 cm. Length = 40 cm. So, Putting these value we get, (41)^2=(40)^2+(Width)^2 (Width)^2=(41)^2-(40)^2 (Width)^2=1681-1600 (Width)^2=81 Width=9cm Hence the width of the rectangle is 9 cm. So The PERIMETER of the rectangle = 2 ( Length + Width ) = 2 ( 40 cm + 9 cm ) = 2 x 49 cm = 98 cm Hence the perimeter of the rectangle is 98 cm.

Find the perimeter of rectangle whole length is 40 cm and diagonal is 41 cm

Answer»

Answer:

98cm

Step-by-step explanation:

By PYTHAGORAS theorem,

(DIAGONAL)^2=(Length)^2+(Width)^2

Now as given in the question,

Diagonal = 41 cm.

Length = 40 cm.

So, Putting these value we get,

(41)^2=(40)^2+(Width)^2

(Width)^2=(41)^2-(40)^2

(Width)^2=1681-1600

(Width)^2=81

Width=9cm

Hence the width of the rectangle is 9 cm.

The PERIMETER of the rectangle = 2 ( Length + Width )

= 2 ( 40 cm + 9 cm )

= 2 x 49 cm

= 98 cm

Hence the perimeter of the rectangle is 98 cm.