Find the perimeter of rectangle whose breadth is 24cm and a diagonal i

1.	Find the perimeter of rectangle whose breadth is 24cm and a diagonal is 25cm
Answer» Answer: $breadth \: of \: rectangle = 24cm$ We know that, the diagonal of a rectangle divides it into two right ANGLE traingle. So, we can apply Pythagoras theorem. $let \: us \: take \: base \: = 24 \: cm$ $and \: diagonal \: = \: hypotenuse \: = 25 \: cm$ Let's apply Pythagoras theorem ${hypotenuse}^{<klux>2</klux>} = \: \: {base}^{2} + {<klux>PERPENDICULAR</klux>}^{2}$ Now Put The Value ${25}^{2} = {24}^{2} + {perpendicular}^{2}$ $625 - 576 = {perpendicular}^{2}$ $49 = {perpendicular}^{2}$ $\sqrt{49} = perpendicular$ $7 = perpendicular$ So , Perpendicular = Length = 7 We know that. PERIMETER of Rectangle = 2(l +b) $= 2(l + b)$ $= 2 (7 + 24)$ $= 2(31)$ $= 62 \: cm \: answer$ Hence the Perimeter of Rectangle is *62CM*