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Find the perimeter of the given triangle.Hypotenuse = \(\sqrt{....^2+\,....^2}=\sqrt{....}\)Perimeter = 2 + 3 + ……… |
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Answer» Hypotenuse = \(\sqrt{13;}\sqrt{2^2+5^2}=\sqrt{4+9}\) Perimeter = 2 + 3 + \(\sqrt{13}=5+\sqrt{13}\) |
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