Find the period of revolution of an electron having a kinetic energy of 1.5 MeV in a magnetic field with induction 0.02 T. The electron moves in a plane perpendicular to the lines of force.

Find the period of revolution of an electron having a kinetic energy o

1.	Find the period of revolution of an electron having a kinetic energy of 1.5 MeV in a magnetic field with induction 0.02 T. The electron moves in a plane perpendicular to the lines of force.
Answer» Solution :This is a relativistic ELECTRON, since its tolal energy `epsi=epsi_(0)+ K= 0.511 + 1.5 =2.0 MeV` is MUCH greater than its rest energy. We obtain from `mu^2//R= euB` `T=(2piR)/(u)=(2pim)/(E B)=(2pi epsi)/(e Bc^2)`

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Find the period of revolution of an electron having a kinetic energy of 1.5 MeV in a magnetic field with induction 0.02 T. The electron moves in a plane perpendicular to the lines of force.

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